f(x)以 (x^2+x-3) 除之餘4x-3 ,以 x-2 除之餘8 ,則以 (x-2)(x^2+x-3) 除之,餘式為
(A) x^2+x+2 (B) x^2+5x-6 (C) x^2-x+6 (D)x^2-5x+14
答案....(B)
駭客數學p3-12
版主: thepiano
Re: 駭客數學p3-12
設 f(x) = (x^2 + x - 3)(x - 2)q(x) + k(x^2 + x - 3) + 4x - 3
f(2) = 3k + 5 = 8
k = 1
所求 = x^2 + x - 3 + 4x - 3 = x^2 + 5x - 6
f(2) = 3k + 5 = 8
k = 1
所求 = x^2 + x - 3 + 4x - 3 = x^2 + 5x - 6